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0=4x^2-24x-30
We move all terms to the left:
0-(4x^2-24x-30)=0
We add all the numbers together, and all the variables
-(4x^2-24x-30)=0
We get rid of parentheses
-4x^2+24x+30=0
a = -4; b = 24; c = +30;
Δ = b2-4ac
Δ = 242-4·(-4)·30
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{66}}{2*-4}=\frac{-24-4\sqrt{66}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{66}}{2*-4}=\frac{-24+4\sqrt{66}}{-8} $
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